Ratios can be used in trig – if it’s 1.5 times as long as it is tall, tan(\theta) = \frac{2}{3}, which then allows you to find the lengths of the other two sides easily so long as you have a calculator.
Right, but why bring theta into it at all? TV screens are as a hypotenuse (a²+b²) with a fixed ratio (a/b=16/9), so you just need to solve for a and b.
You don’t have to, but it seems perfectly easy since you don’t have to write anything down to solve it. c*sin(arctan(b/a)) gives b, and c*cos(arctan(b/a)) gives a. I’m not disputing that you can do it without, but I don’t think it’s necessarily any quicker or easier.
I’m trying to figure out how you need trig for that. Just the Pythagorean theorem and ratios seem sufficient to me.
Ratios can be used in trig – if it’s 1.5 times as long as it is tall, tan(\theta) = \frac{2}{3}, which then allows you to find the lengths of the other two sides easily so long as you have a calculator.
Right, but why bring theta into it at all? TV screens are as a hypotenuse (a²+b²) with a fixed ratio (a/b=16/9), so you just need to solve for a and b.
You don’t have to, but it seems perfectly easy since you don’t have to write anything down to solve it. c*sin(arctan(b/a)) gives b, and c*cos(arctan(b/a)) gives a. I’m not disputing that you can do it without, but I don’t think it’s necessarily any quicker or easier.
If it works it works. I just never would have thought to do it that way.
I am trying to figure out why you’d even need that.
The measurements of the product is usually written in the tech spec.